Created: 2022-08-20
Tags: #fleeting
for (i = 0; i < n; i++)
for (j = 0; j < m; j++)
if (a[i] == b[j])
goto found;
/* didn't find any common element */
...
found:
/* got one: a[i] == b[j] */
...
You can use code without goto that does the same thing
for (i = 0; i < n && !found; i++)
for (j = 0; j < m && !found; j++)
if (a[i] == b[j])
found = 1;
if (found)
/* got one: a[i-1] == b[j-1] */
...